37512014
Description
Quiz by BOTE FÉ NA MATEMÁTICA, updated more than 1 year ago
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Created by BOTE FÉ NA MATEMÁTICA
over 2 years ago
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Question 1
Question
Quais das expressões a seguir não fazem sentido?
Answer
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\(\int_{0}^{1}\int_{1}^{y}f(x, y)dydx\)
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\(\int_{0}^{1}\int_{1}^{x}f(x, y)dydx\)
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\(\int_{1}^{y}\int_{0}^{1}f(x, y)dydx\)
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\(\int_{0}^{1}\int_{x}^{1}f(x, y)dydx\)
Question 2
Question
Qual das quatro regiões, na figura dada, é o domínio de integração de \(\int_{-\sqrt{2}/2}^{0}\int_{-x}^{\sqrt{1-x^2}}f(x, y)dydx\)?
Answer
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A
-
B
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C
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D
Question 3
Question
Calcule a área limitada pelas curvas \(y=x^2\) e \(y = x+2\).
Answer
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\(\frac{9}{2}\)
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\(\frac{19}{12}\)
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\(\frac{19}{4}\)
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\(\frac{11}{12}\)
Question 4
Question
Calcule a área da Elipse \(\frac{x^2}{16} + \frac{y^2}{25} = 1\) usando integral dupla.
Answer
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\(20\pi\)
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\(10\pi\)
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\(\pi\)
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20
Question 5
Question
Determine o volume do sólido limitado pelo plano \(z=0\) e pelo paraboloide \(z = 4 - x^2 - y^2\)
Answer
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\(8\pi\)
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\(\frac{\pi}{2}\)
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\(4\pi\)
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\(16\pi\)
Question 6
Question
Determine o volume do sólido que está sob o paraboloide \(z = x^2 + y^2\), acima do plano xy e dentro do cilindro \(x^2 + y^2 = 2y\).
Answer
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\(\frac{3\pi}{2}\)
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\(\frac{\pi}{2}\)
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\(\frac{3\pi}{4}\)
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\(\frac{\pi}{4}\)
Question 7
Question
Marque a alternativa que apresenta a integral \(\int_{4}^{9}\int_{\sqrt{y}}^{y}f(x, y)dxdy\).
Answer
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\(\int_{2}^{3}\int_{4}^{x^2}f(x, y)dydx +\int_{3}^{4}\int_{4}^{9}f(x, y)dydx+ \int_{4}^{9}\int_{x}^{9}f(x, y)dydx\)
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\(\int_{2}^{3}\int_{x^2}^{9}f(x, y)dxdy+\int_{3}^{9}\int_{x}^{9}f(x, y)dydx\)
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\(\int_{2}^{3}\int_{9}^{x^2}\)f(x, y)dydx
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\(\int_{2}^{3}\int_{9}^{x^2}\)f(x, y)dxdy
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