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Created by Tech Wilkinson
about 11 years ago
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Question | Answer |
discriminant | b2−4ac |
equation of straight line through (x1,y1) with gradient m | y−y1=m(x−x1) |
perpendicular straight lines with gradients m1 and m2 | m1m2=−1 |
equation of circle with centre (a,b) and radius r | (x−a)2+(y−b)2=r2 |
differentiation of y=xn | dydx=nxn−1 |
differentiation of y=f(x)+g(x) | dydx=f′(x)+g′(x) |
Min / Max / Point of inflection (2nd derivative) | d2ydx2=0 |
Minimum point (2nd derivative) | d2ydx2>0 |
Maximum point (2nd derivative) | d2ydx2<0 |
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