Stats 151 - Sample Distribution and Probability in Normal Distribution

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Chemistry 101 Stats 151 Flashcards on Stats 151 - Sample Distribution and Probability in Normal Distribution, created by jennabarnes12387 on 24/02/2014.
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Flashcards by jennabarnes12387, updated more than 1 year ago
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Created by jennabarnes12387 almost 11 years ago
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if a school has a GPA of 2.8 and a standard deviation of 0.8 what percent of students have a GPA less then 2? greater then 3? P(x< or equal to 2) = P(Z < -1) = 0.1587 P(x>3) = P(Z>0.25)=1-P(X< of equal to 0.25) = 1-0.5987 = 0.4013
between 2 and 3? - P(2<x<3) = P(-1<Z<0.25)P(Z < 0.25) – P(Z<-1)0.5987 – 0.1587 = 0.4400
What is the minimum GPA needed to be in the top 10% creates two areas, 0.1, and 0.9. find the Z score for 0.9 which is 1.28 and then use to solve for x in the equation Z = x-u/sigma
what is a normal probability plot? a scatter plot of the normal Z score pairs
how do you find the Z score pairs? order the data from smallest to largest. then us table 3 to find the normal sores using the z scores. then plot the data (z,x)
the mean of X is always equal to____ no matter the width of the distribution? x bar
what is parameter? a number calculating a population and describes the characteristics of a population
what is a statistic? a number calculated from and describing the characteristics of a sample
how do we find x bar? u, sigma/ square root of n
the avergae adult weight is 175 pounds with a standard deviation of 25 pounds. an elevator has a weight limit of 10 people or 2000 pounds. What is the probability that the ten people who get on an elevator exceed the weight limit? P(overload) = x1 + x2 + ………x10 > 2000 pounds = X1 + x2 + ……….. x10 / 2 = 2000/10 = 200. the Z score for 200 is 3.16. 1-p(z < or equal to 3.16) = 0.9992 = 0.0081-p(z < or equal to 3.16) = 0.9992 = 0.008
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