31687027
Description
Quiz by IWKZ Tutorium, updated more than 1 year ago
|
|
Created by IWKZ Tutorium
almost 3 years ago
|
|
Question 1
Question
Lösen Sie diese Polynomdivision!
\[\frac{x^5 + 3x^4 - 5x^3 - 15x^2 + 4x + 12}{x^3 + 4x^2 + x - 6}\]
Answer
-
\[x^2 - x + 2\]
-
\[2x^2 + 3x - 2\]
-
\[x^2 - x - 2\]
-
\[x^2 - 2x - 1\]
-
Ich gebe auf!
Question 2
Question
Lösen Sie diese Polynomdivision!
\[\frac{x^4 - 43x^2 + 18x + 360}{(x + 1)^2 - 25}\]
Answer
-
\[x^2 - 2x - 15\]
-
\[x^2 - 2x - 15 + \frac{1}{x^2 + 2x - 24}\]
-
\[3x^2 - x - 4\]
-
\[x^2 - 6x - 12\]
-
Ich gebe auf!
Question 3
Question
Lösen Sie diese Polynomdivision!
\[\frac{6x^4 + 5x^3 + 4x - 4}{2x^2 + x - 1}\]
Answer
-
\[3x^2 - x + 2 + \frac{4x - 3}{2x^2 + x - 2}\]
-
\[3x^2 + x + 1 + \frac{4x - 3}{2x^2 + x - 1}\]
-
\[3x^2 + x + 1\]
-
\[3x^2 - x + 2\]
-
Ich gebe auf!
Question 4
Question
Lösen Sie diese Polynomdivision!
\[\frac{2x^3 - 3x + 1}{2x - 1}\]
Answer
-
\[x^2 + \frac{1}{2}x - \frac{5}{4} - \frac{1}{4\cdot(2x - 1)}\]
-
\[x^2 + x - \frac{5}{2} - \frac{1}{2\cdot(2x - 1)}\]
-
\[x^2 - x + 27 - \frac{1}{2x - 1}\]
-
\[x^2 + \frac{\frac{5}{2}x + 1}{2x - 1}\]
-
Ich gebe auf!
Want to create your own Quizzes for free with GoConqr? Learn more.