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The SAT Math test essentials list

lizcortland

Potęgi,pierwiastki i logarytmy

Description

Matematyka, 2 liceum

Flashcards by Monika Bączek, updated more than 1 year ago

	Created by Monika Bączek almost 8 years ago

104

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Resource summary

Question	Answer
$a^{0}=$	1
$a^{n}*a^{m}=$	$a^{m+n}$
$a^{n}:a^{m}=$	$a^{m-n}$
$(a^{n})^{m}=$	$a^{m*n}$
$a^{\frac {1}{n}}=$	$\sqrt[n]a$
$a^{\frac {k}{n}}=$	$\sqrt[n]a^{k}$
$log_{a}b=x \leftrightarrow$	$a^{x}=b$
$log_{a}b-log_{a}c=$	$log_{a}(\frac {b}{c})$
$log_{a}b^{c}=$	$c*log_{a}b$
$log_{a}b+log_{a}c=$	$log_{a}(b*c)$
$(2^{-8})^{3}=$	$2^{-24}$
$17^{6}:17^{-3}=$	$17^{9}$
$15^{-3}*15^{-7}=$	$15^{-10}$
$6^{-5}:6^{-2}=$	$6^{-3}$
$2^{82}:4^{40}=$	$2^{2}$
$25^{3}*0,2^{-6}=$	$5^{12}$
$5^{8}:0,2^{-7}=$	$5$
$\frac {125^{3}(5^{-2})^{4}}{25^{4}25*^{-5}}=$	$125$
$\frac {7^{5}:49}{7}*(\frac {1}{7})^{-2}=$	$7^{4}$
$8^{\frac {1}{3}}=$	2
$144^{-\frac {1}{2}}=$	$\frac {1}{12}$
$64^{\frac {4}{3}}=$	256
$9^{-1,5}=$	$\frac {1}{27}$
$log_{2}32=$	5
$log_{7}1=$	0
$log10^{5}=$	10
$log_{2}80+log_{2}0,1=$	3
$log_{3}4,5+log_{3}2=$	2
$log_{2}7-log_{2}56=$	-3
$log_{8}8^{\frac{1}{3}}=$	$\frac{1}{3}$

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