61979
| Question | Answer |
| Laws of Logs | logaM + logaN = logaMN logaM - logaN = logaM/N KlogaM = logaM(K) |
| LogaA? | 1 |
| loga1=? | 0 |
| logaX =? | X |
| a(logaX)=? | X |
| How to solve equation in form a(x) = b? | Take logs of both sides |
| y=a(x) --> ? | logaY = x |
| graph of y=a(x)? | Positive for all values of x passes through (0,1) |
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