285871
Description
Flashcards by Louise Addison, updated more than 1 year ago
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Created by Louise Addison
over 10 years ago
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| Question | Answer |
| If I want to find the gradient at a point... | I need to differentiate and then substitute in the x-value |
| If I want to find a point with a certain gradient... | I need to differentiate, set the gradient function equal to the gradient and then solve for x. |
| If I want to find a maximum... | I need to differentiate, set the derivative equal to 0 and solve for x. Then find the maximum by substituting into the orginal formula. |
| If I want to find the distance at a point in time... | I need to anti-differentiate the speed formula and then substitute in t. |
| If I want to find the acceleration at a point in time... | I need to differentiate the speed formula and then substitute in t. |
| If I want to find the speed at a point in time... | I need to differentiate the distance formula OR anti-differentiate the acceleration formula, and then sustitute in t. |
| If I want to find the original function... | I need to anti-differentiate and then substitute in a point to find the value of c. |
| Find the rate of change at a point... | I need to differentiate and substitute in the x value. |
| If I want to find the equation of a tangent... | I need to find the gradient at that point and then substitute into y-y1=m(x-x1). |
| If I want to find the equation of a normal... | I need to find the gradient at that point and then find the gradient of the normal (use m1 x m2 = -1). I then substitute into y-y1=m(x-x1). |
| If I want to find out where a function is increasing... | I need to find the gradient function, set it to >0 and then solve for x. |
| If I want to find out where a function is decreasing... | I need to find the gradient function, set it to <0 and then solve for x. |
| If I want to prove a point is a maximum (or a minimum)... | I need to differentiate twice and then substitute in the x value. If f''(x)<0 it is a maximum. If f''(x)>0 it is a mininum. |
| If I want to find a point on the original curve or function... | I need to anti-differentiate and use a known point to find c. I can then substitue in x to find the y value for that point. |
| If I want to sketch the gradient function from a function... | I need to convert turning points to x-intercepts, increasing parts are above the x-axis and decreasing parts are below the x-axis. |
| If I want to sketch a function from a gradient function. | I need to convert x-intercepts to turning points, parts above the x-axis are increasing and parts below the x-axis are decreasing. |
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