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Created by Daniel Cox
about 9 years ago
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Copied by Daniel Cox
about 9 years ago
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Copied by Charlotte Cook
over 7 years ago
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Question | Answer |
Formula for the gradient of a line joining two points |
m=y2−y1x2−x1 |
The midpoint of (x1,y1) and (x2,y2) is... |
(x1+x22,y1+y22)
Think of this as the mean of the coordinates (x1,y1) and (x2,y2)
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The quadratic equation formula for solving ax2+bx+c=0 |
x=−b±√b2−4ac2a |
A line has gradient m. A line perpendicular to this will have a gradient of... |
−1m |
If we know the gradient of a line and a point on the line, a formula to work out the equation of the line is... |
y−y1=m(x−x1) |
Formula for the distance between two points... |
√(x2−x1)2+(y2−y1)2 |
To find where two graphs intersect each other... | ... solve their equations simultaneously. |
To simplify a√b... (a.k.a. 'rationalising the denominator') |
Multiply by √b√b |
To simplify ab+√c... (a.k.a. 'rationalising the denominator') |
Multiply by b−√cb−√c |
(√m)3=... |
(√m)3=√m√m√m=m√m |
√a×√b=... |
√a×√b=√ab |
√a√b=... |
√a√b=√ab |
To find the gradient of a curve at any point, use... | Differentiation |
Parallel lines have the same... | Gradient |
To find the gradient of the line ax+by+c=0... | Rearrange into the form y=mx+c. The value of m is the gradient. |
Where is the vertex of the graph y=(x+a)2+b ?
|
(−a,b) |
The discriminant of ax2+bx+c is... |
b2−4ac |
The discriminant of a quadratic equation tells us... | How many roots (or solutions) it has. This will be how many times it crosses the x-axis |
If a quadratic equation has two distinct real roots, what do we know about the discriminant? |
b2−4ac>0 |
If a quadratic equation has two equal roots, what do we know about the discriminant? |
b2−4ac=0 |
If a quadratic equation has no real roots, what do we know about the discriminant? |
b2−4ac<0 |
Here is the graph of y=x2−8x+7. Use it to solve the quadratic inequality x2−8x+7>0 | x<1 or x>7 These are the red sections of the curve. Note - do not write x<1 and x>7 - the word 'and' implies x would need to be <1 and >7 at the same time... which is clearly not possible! |
If y=axn, then dydx=... |
dydx=anxn−1 |
If y=axn, then ∫ydx=... |
∫axndx=axn+1n+1+c |
What effect will the transformation y=f(x)+a have on the graph of y=f(x)? | Translation a units in the y direction. i.e. the graph will move UP by a units |
What effect will the transformation y=f(x+a) have on the graph of y=f(x)? | Translation −a units in the x direction. i.e. the graph will move LEFT by a units |
What effect will the transformation y=af(x) have on the graph of y=f(x)? | Stretch, scale factor a in the y direction. i.e. the y values will be multiplied by a |
What effect will the transformation y=f(ax) have on the graph of y=f(x)? | Stretch, scale factor 1a in the x direction. i.e. the x values will be divided by a [This could also be described as a 'squash', scale factor a in the x direction] |
If we differentiate y twice with respect to x, what do we get? |
d2ydx2 |
What effect will the transformation y=f(−x) have on the graph of y=f(x)? | Reflection in the y axis |
What effect will the transformation y=−f(x) have on the graph of y=f(x)? | Reflection in the x axis |
(n√x)m=...? |
(n√x)m=xmn |
a−n=...? |
a−n=1an |
a0=...? |
a0=1 |
x1n=...? |
x1n=n√x |
(ab)n=...? |
(ab)n=anbn |
What does the graph of y=1x look like? | |
What does the graph of y=ax, where a>0 look like? | The x axis is an asymptote |
What do the graphs y=x3 and y=−x3 look like? | |
What does ∑4r=1ar mean? |
4∑r=1ar=a1+a2+a3+a4 |
Formula for the nth term of an arithmetic sequence... [given in the formulae booklet] |
un=a+(n−1)d |
Formula for the sum of the first n terms of an arithmetic sequence... [given in the formulae booklet] |
Sn=n2(2a+(n−1)d)
or
Sn=n2(a+l)
where l is the last term
|
If we are given dydx or f′(x) and told to find y or f(x), we need to... | Integrate [remember to include +c] |
Integration is the reverse of ... ? | Differentiation |
Differentiation is the reverse of ... ? | Integration |
The rate of change of y with respect to x is also called...? |
dydx |
The formula for finding the roots of ax2+bx+c=0 |
x=−b±√b2−4ac2a |
am÷an=...? |
am÷an=am−n |
(am)n=...? |
(am)n=amn |
To simplify ab−√c... (a.k.a. 'rationalising the denominator') |
Multiply by b+√cb+√c |
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