Edexcel Core 1 Maths - Key Facts

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Key points and important formulae for the Edexcel GCE Maths C1 module
Charlotte Cook
Flashcards by Charlotte Cook, updated more than 1 year ago More Less
Daniel Cox
Created by Daniel Cox about 9 years ago
Daniel Cox
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Charlotte Cook
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Question Answer
Formula for the gradient of a line joining two points m=y2y1x2x1
The midpoint of (x1,y1) and (x2,y2) is... (x1+x22,y1+y22)
Think of this as the mean of the coordinates (x1,y1) and (x2,y2)
The quadratic equation formula for solving ax2+bx+c=0
x=b±b24ac2a
A line has gradient m. A line perpendicular to this will have a gradient of... 1m
If we know the gradient of a line and a point on the line, a formula to work out the equation of the line is... yy1=m(xx1)
Formula for the distance between two points... (x2x1)2+(y2y1)2
To find where two graphs intersect each other... ... solve their equations simultaneously.
To simplify ab... (a.k.a. 'rationalising the denominator') Multiply by bb
To simplify ab+c... (a.k.a. 'rationalising the denominator') Multiply by bcbc
(m)3=...
(m)3=mmm=mm
a×b=...
a×b=ab
ab=...
ab=ab
To find the gradient of a curve at any point, use... Differentiation
Parallel lines have the same... Gradient
To find the gradient of the line ax+by+c=0... Rearrange into the form y=mx+c. The value of m is the gradient.
Where is the vertex of the graph y=(x+a)2+b
?
(a,b)
The discriminant of ax2+bx+c is... b24ac
The discriminant of a quadratic equation tells us... How many roots (or solutions) it has. This will be how many times it crosses the x-axis
If a quadratic equation has two distinct real roots, what do we know about the discriminant? b24ac>0
If a quadratic equation has two equal roots, what do we know about the discriminant? b24ac=0
If a quadratic equation has no real roots, what do we know about the discriminant? b24ac<0
Here is the graph of y=x28x+7. Use it to solve the quadratic inequality x28x+7>0 x<1 or x>7 These are the red sections of the curve. Note - do not write x<1 and x>7 - the word 'and' implies x would need to be <1 and >7 at the same time... which is clearly not possible!
If y=axn, then dydx=... dydx=anxn1
If y=axn, then ydx=... axndx=axn+1n+1+c
What effect will the transformation y=f(x)+a have on the graph of y=f(x)? Translation a units in the y direction. i.e. the graph will move UP by a units
What effect will the transformation y=f(x+a) have on the graph of y=f(x)? Translation a units in the x direction. i.e. the graph will move LEFT by a units
What effect will the transformation y=af(x) have on the graph of y=f(x)? Stretch, scale factor a in the y direction. i.e. the y values will be multiplied by a
What effect will the transformation y=f(ax) have on the graph of y=f(x)? Stretch, scale factor 1a in the x direction. i.e. the x values will be divided by a [This could also be described as a 'squash', scale factor a in the x direction]
If we differentiate y twice with respect to x, what do we get? d2ydx2
What effect will the transformation y=f(x) have on the graph of y=f(x)? Reflection in the y axis
What effect will the transformation y=f(x) have on the graph of y=f(x)? Reflection in the x axis
(nx)m=...?
(nx)m=xmn
an=...?
an=1an
a0=...?
a0=1
x1n=...?
x1n=nx
(ab)n=...?
(ab)n=anbn
What does the graph of y=1x look like?
What does the graph of y=ax, where a>0 look like? The x axis is an asymptote
What do the graphs y=x3 and y=x3 look like?
What does 4r=1ar mean? 4r=1ar=a1+a2+a3+a4
Formula for the nth term of an arithmetic sequence... [given in the formulae booklet] un=a+(n1)d
Formula for the sum of the first n terms of an arithmetic sequence... [given in the formulae booklet] Sn=n2(2a+(n1)d)
or Sn=n2(a+l)
where l is the last term
If we are given dydx or f(x) and told to find y or f(x), we need to... Integrate [remember to include +c]
Integration is the reverse of ... ? Differentiation
Differentiation is the reverse of ... ? Integration
The rate of change of y with respect to x is also called...? dydx
The formula for finding the roots of ax2+bx+c=0
x=b±b24ac2a
am÷an=...?
am÷an=amn
(am)n=...?
(am)n=amn
To simplify abc... (a.k.a. 'rationalising the denominator') Multiply by b+cb+c
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