1º Lista de exercícios - Limites

Quiz by Professor José, created more than 1 year ago

Olá, sou o professor José. Aqui está a primeira lista de exercícios do nosso Curso de Cálculo.

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	Created by Professor José about 10 years ago

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Olá, sou o professor José. Aqui está a primeira lista de exercícios do nosso Curso de Cálculo.

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1º Lista de exercícios - Limites

Question 1 of 7 Question 1 of 7

O valor de $\displaystyle\lim_{x \to 1} (2x+7)$ é:

Select one of the following:

Explanation

Question 2 of 7 Question 2 of 7

O valor de $\displaystyle\lim_{x \to 2} (x^2-2x+1)$

Select one of the following:

Explanation

Question 3 of 7 Question 3 of 7

$\displaystyle\lim_{x \to -1}(\frac{x³+2}{x-4})$ :

Select one of the following:

Explanation

Question 4 of 7 Question 4 of 7

Com relação a $\displaystyle\lim_{x \to 0}(\frac{x}{\sqrt{x+1}-1})$ , podemos afirmar que:

Select one of the following:

Explanation

Question 5 of 7 Question 5 of 7

Qual o limite de f quando x está próximo de 1, se f(x) = $\frac{\sqrt[5]{x} -1}{\sqrt[4]{x} -1}$ ?

Select one of the following:

Explanation

Question 6 of 7 Question 6 of 7

Resolva $\displaystyle\lim_{x \to 4}(\frac{x^2-16}{x-4})$

Select one of the following:

Explanation

Question 7 of 7 Question 7 of 7

$\displaystyle\lim_{x \to 1}\sqrt {\frac{x}{x+8}}$

Select one of the following:

Explanation

Olá, sou o professor José. Aqui está a primeira lista de exercícios do nosso Curso de Cálculo.

0 comments

1º Lista de exercícios - Limites

Question 1 of 7 Question 1 of 7

O valor de limx→1(2x+7)\displaystyle\lim_{x \to 1} (2x+7) é:

Select one of the following:

Explanation

Question 2 of 7 Question 2 of 7

O valor de limx→2(x2−2x+1)\displaystyle\lim_{x \to 2} (x^2-2x+1)

Select one of the following:

Explanation

Question 3 of 7 Question 3 of 7

\displaystyle\lim_{x \to -1}(\frac{x³+2}{x-4})\displaystyle\lim_{x \to -1}(\frac{x³+2}{x-4}) :

Select one of the following:

Explanation

Question 4 of 7 Question 4 of 7

Com relação a \displaystyle\lim_{x \to 0}(\frac{x}{\sqrt{x+1}-1})\displaystyle\lim_{x \to 0}(\frac{x}{\sqrt{x+1}-1}), podemos afirmar que:

Select one of the following:

Explanation

Question 5 of 7 Question 5 of 7

Qual o limite de f quando x está próximo de 1, se f(x) = \frac{\sqrt[5]{x} -1}{\sqrt[4]{x} -1}\frac{\sqrt[5]{x} -1}{\sqrt[4]{x} -1} ?

Select one of the following:

Explanation

Question 6 of 7 Question 6 of 7

Resolva \displaystyle\lim_{x \to 4}(\frac{x^2-16}{x-4})\displaystyle\lim_{x \to 4}(\frac{x^2-16}{x-4})

Select one of the following:

Explanation

Question 7 of 7 Question 7 of 7

\displaystyle\lim_{x \to 1}\sqrt {\frac{x}{x+8}}\displaystyle\lim_{x \to 1}\sqrt {\frac{x}{x+8}}

Select one of the following:

Explanation

O valor de $\displaystyle\lim_{x \to 1} (2x+7)$ é:

O valor de $\displaystyle\lim_{x \to 2} (x^2-2x+1)$

$\displaystyle\lim_{x \to -1}(\frac{x³+2}{x-4})$ :

Com relação a $\displaystyle\lim_{x \to 0}(\frac{x}{\sqrt{x+1}-1})$ , podemos afirmar que:

Qual o limite de f quando x está próximo de 1, se f(x) = $\frac{\sqrt[5]{x} -1}{\sqrt[4]{x} -1}$ ?

Resolva $\displaystyle\lim_{x \to 4}(\frac{x^2-16}{x-4})$

$\displaystyle\lim_{x \to 1}\sqrt {\frac{x}{x+8}}$